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The following questions are forwarded from a school mail:I don't know how to fully factor the following problems:x^2+5x+3=0x^2+3x+1=05=-2x+x^2
Sorry, the instruction was wrong and misleading, and has been corrected. Just use quadratic formula to solve them. Worksheet_08:Exercise:3-e) x^2+5x+3=0x = (-5 +- sqrt(5^2 - 4(1)(3)))/((2)(1))= (-5 +- sqrt(13))/25-c) x^2+3x+1=0x = (-3 +- sqrt(3^2 - 4(1)(1)))/((2)(1))= (-3 +- sqrt(5))/2Homework:6) 5=-2x+x^2x^2 - 2x - 5 = 0x = (-(-2) +- sqrt((-2)^2 - 4(1)(-5)))/((2)(1))= (2 +- sqrt(24))/2= (2 +- 2 sqrt(6))/2= 1 +- sqrt(6)
The following questions are forwarded from a school mail:
ReplyDeleteI don't know how to fully factor the following problems:
x^2+5x+3=0
x^2+3x+1=0
5=-2x+x^2
Sorry, the instruction was wrong and misleading, and has been corrected. Just use quadratic formula to solve them.
DeleteWorksheet_08:
Exercise:
3-e) x^2+5x+3=0
x = (-5 +- sqrt(5^2 - 4(1)(3)))/((2)(1))
= (-5 +- sqrt(13))/2
5-c) x^2+3x+1=0
x = (-3 +- sqrt(3^2 - 4(1)(1)))/((2)(1))
= (-3 +- sqrt(5))/2
Homework:
6) 5=-2x+x^2
x^2 - 2x - 5 = 0
x = (-(-2) +- sqrt((-2)^2 - 4(1)(-5)))/((2)(1))
= (2 +- sqrt(24))/2
= (2 +- 2 sqrt(6))/2
= 1 +- sqrt(6)